Lecturer : Madhu Sudan Scribe : Anastasios Sidiropoulos 1 Overview
نویسنده
چکیده
n Proof Assume that m > 2n. We define vectors c̃1, . . . , c̃m ≈ R, such that for each i, with � {−1, 1} ci, and for each i, with 1 � j � n, the jth coordinate of ̃ 1 � i � n, ̃ ci is −1, iff the jth bit of ci is 1. Note that if �(ci, cj ) � n/2, then this implies →c̃i, c̃j � 0. Intuitively, this means that if two codewords ⊂ ci, and cj have large Hamming distance, then the angle between the corresponding vectors ̃ cj , ci, and ̃ should be large. Pick a random unit vector x � R . We have that w.h.p., →x, c̃i = 0, for all i, with 1 � i � m. ⊂ √ Moreover, since there are m codewords, either x, or −x has strictly positive inner product with at least m/2 of the c̃is. We can assume w.l.o.g., that this holds for x. Since m > 2n, it follows that there exist n+ 1 vectors having strictly positive inner product with x. W.l.o.g., assume that these are the vectors c̃1, . . . , c̃n+1. Observe that a set of n+ 1 vectors in an n-dimensional space, cannot be linear independent. Thus, we can assume that there exist �1, . . . , �n+1 � R, with �i > 0, for each i, with 1 � i � j, and �i � 0, for each i, with j < i � n+ 1, such that
منابع مشابه
On the Work of Madhu Sudan, Volume 50, Number 1
Madhu Sudan is the recipient of the 2002 Nevanlinna Prize. Sudan has made fundamental contributions to two major areas of research, the connections between them, and their applications. The first area is coding theory. Established by Shannon and Hamming over fifty years ago, it is the mathematical study of the possibility of, and the limits on, reliable communication over noisy media. The secon...
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It has been recently shown that any graph of genus g > 0 can be stochastically embedded into a distribution over planar graphs, with distortion O(log(g + 1)) [Sidiropoulos, FOCS 2010]. This embedding can be computed in polynomial time, provided that a drawing of the input graph into a genus-g surface is given. We show how to compute the above embedding without having such a drawing. This implie...
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